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Capacitor $C_1$ of capacitance $1 \mu \mathrm{F}$ and capacitor $C_2$ of capacitance $2 \mu \mathrm{F}$ are separately charged fully by a common battery. The two capacitors are then separately allowed to discharged through equal resistors at time $t=0$
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the currents in the two discharging circuits at $t=0$ are equal but non-zero
Here, $V_0$ and $R$ in the two $C R$ circuits are same, hence the currents in the two discharging circuits at $t=0\left(V_0 / R\right)$ will be same.
We know that, time constant of a resistance and capacitance circuit is $C R$. Here, time constant of first circuit (capacity $C_1=1 \mu F$ ) is half of the time constant of second circuit (capacity $C_2=2 \mu F$ ). Hence, $C_1$ loses $50 \%$ its initial charge sooner.
We know that, time constant of a resistance and capacitance circuit is $C R$. Here, time constant of first circuit (capacity $C_1=1 \mu F$ ) is half of the time constant of second circuit (capacity $C_2=2 \mu F$ ). Hence, $C_1$ loses $50 \%$ its initial charge sooner.
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