Capacitor C 1 of capacity 1 μ F and capacitor C 2 of capacity 2 μ F are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at t = 0

Question

Capacitor C 1 of capacity 1 μ F and capacitor C 2 of capacity 2 μ F are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at t = 0, At t = 0 the value of current in the circuit containing 1 μ F is more than current in the circuit containing 2 μ F, At t = 0 the current in 2 μ F capacitor circuit is more than current in 1 μ F capacitor circuit, 1 μ F capacitor losses 50 % charge sooner than 2 μ F capacitor, 2 μF capacitor losses 50 % charge sooner than 1 μF capacitor

MARKS App · Accepted Answer

Total potential difference E 0 is given to both of the capacitor. The two capacitors are then separately allowed to discharge through same resistors. Since both capacitors are charged to same potential difference hence current at t = 0 , I 0 = E 0 R will be same in both circuits. Time taken in 50 % discharging = R C l n ( 2 ) As 1 s t capacitance is 50% less than that of 2 n d capacitance, hence 1 μ F will take less time compared to 2 μ F

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