Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Case \(-1:\) An ideal gas of molecular weight \(M\) at temperature \(T\).
Case \(-2:\) Another ideal gas of molecular weight \(2 \mathrm{M}\) at temperature \(\mathrm{T} / 2\)
Identify the correct statement in context of above two cases.
ChemistryStates of MatterWBJEEWBJEE 2023
Options:
  • A Average kinetic energy and avereage speed will be the same in the two cases
  • B Both the averages are halved
  • C Both the averages are doubled
  • D Only average speed is halved in the second case
Solution:
1722 Upvotes Verified Answer
The correct answer is: Both the averages are halved
Hint : As temperature is halved, average \(K E\) is halved.
Average speed \((C) \propto \sqrt{\frac{T}{M}}\)
In case \(-I,(C) \propto \sqrt{\frac{T}{M}}\)
\(\text { In case }-II ~(C) \propto \sqrt{\frac{T}{2 \times 2 M}}=\frac{1}{2} \sqrt{\frac{T}{M}}\)
So average speed is also halved.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.