Certainly, here's the question with additional information: "The electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law: $R~=~{{R}_{0}}\left[ 1+\alpha \left( T-{{T}_{0}} \right) \right]$ The resistance is 101.6 Ω at the triple-point of water (273.16 K), and 165.5 Ω at the normal melting point of lead (600.5 K). Given this information, what is the temperature in Kelvin when the resistance of the thermometer is 123.4 Ω?