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$\quad \mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CCH}_{3} \stackrel{\mathrm{H}_{2} / \mathrm{Pt}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{D}_{2} / \mathrm{Pt}}{\longrightarrow} \mathrm{B}$
The compounds $A$ and $B$, respectively are
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The compounds $A$ and $B$, respectively are
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cis-butene- 2 and meso-2, 3-dideuterobutane
Catalytic hydrogenation of alkynes gives cis-alkene which in turn adds deuterium atoms in presence of $\mathrm{H}_{2}$ again in $\mathrm{ci}$ -manner forming meso -2,3 -dideuterobutane.
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