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$\begin{aligned} & \mathrm{CH}_3\left(\mathrm{CH}_2\right)_4 \mathrm{CH}_3 \underset{773 \mathrm{~K}, 10-20 \text { atm }}{\stackrel{\mathrm{Cr}_2 \mathrm{O}_3 / \mathrm{Al}_2 \mathrm{O}_3}{\longrightarrow}} A \stackrel{\mathrm{Br}_2 / \mathrm{Fe}}{\longrightarrow} B \\ & D \stackrel{\mathrm{H}_2 \mathrm{O}}{\longleftarrow} C \stackrel{\mathrm{Mg}}{\text { ether }} \\ & \end{aligned}$
What is $D$ ?
ChemistryHydrocarbonsAIIMSAIIMS 2009
Options:
  • A
  • B
  • C
  • D
Solution:
2030 Upvotes Verified Answer
The correct answer is:
Benzene can be prepared by cyclization of long chain alkanes on heating at $500-550^{\circ} \mathrm{C}$ under high pressure in presence of catalyst $\mathrm{Cr}_2 \mathrm{O}_3$ supported on alumina or $\mathrm{Pt}-\mathrm{Al}_2 \mathrm{O}_3$ (i.e., catalytic reforming)

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