CH 3 CH 2 CH 2 OH → conc . H 2 SO 4 X → Cl 2 , hν Y , X and Y are

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{CH}_{3} {CH}_{2} {CH}_{2} OH \overset{conc . H_{2} {SO}_{4}}{\to} X \overset{{Cl}_{2}, hν}{\to} Y

, X and Y are

ChemistryAlcohols Phenols and EthersNEET

Options:

A $X = C H_{3} C H_{2} C H_{3}, Y = C H_{3} C H_{2} C H_{2} C l$
B $X = C H_{3} C H = C H_{2}, Y = C H_{2} C l C H = C H_{2}$
C $X = C H_{2} = C H_{2}, Y = C H_{3} C H_{2} C l$
D $X = C H_{3} C H_{2} C H_{3}, Y = C H_{3} C H = C H_{2}$

Solution:

1827 Upvotes Verified Answer

The correct answer is:

X = C H_{3} C H = C H_{2}, Y = C H_{2} C l C H = C H_{2}

{CH}_{3} {CH}_{2} {CH}_{2} OH \overset{conc . H_{2} {SO}_{4}}{\to} \underset{X}{{CH}_{3} CH = {CH}_{2}} \overset{{Cl}_{2}, hv}{\to} \underset{Y}{Cl - {CH}_{2} - CH = {CH}_{2}}

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