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$\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow{\mathrm{NaNO}_2 / \mathrm{HG}} \mathrm{X}$
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The correct answer is:
$\mathrm{CH}_3 \mathrm{COOH}$
Amide, on treating with $\mathrm{HNO}_2$ give acids.
$\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow[\left(\mathrm{HNO}_2\right)]{\mathrm{NaNO}_2 / \mathrm{HCl}} \underset{\text { acetic acid }}{\mathrm{CH}_3 \mathrm{COOH}+\mathrm{N}_2+\mathrm{H}_2 \mathrm{O}}$
$\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow[\left(\mathrm{HNO}_2\right)]{\mathrm{NaNO}_2 / \mathrm{HCl}} \underset{\text { acetic acid }}{\mathrm{CH}_3 \mathrm{COOH}+\mathrm{N}_2+\mathrm{H}_2 \mathrm{O}}$
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