CH 3 COOH → Br 2 / P (Y) → (ii) H 3 O + (i) KCN (X) Here (X) is:

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{CH}_{3} COOH \overset{{Br}_{2} / P}{\to} (Y) \to_{{(ii) H}_{3} O^{+}}^{(i) KCN} (X)

Here (X) is:

ChemistryCarboxylic Acid DerivativesNEET

Options:

A Glycollic acid
B $α$ -Hydroxypropionic acid
C Succinic acid
D Malonic acid

Solution:

1782 Upvotes Verified Answer

The correct answer is: Malonic acid

\begin{matrix} \overset{α}{{CH}_{3}} COOH & \to_{{Br}_{2} / P}^{H.V.Z} & {BrCH}_{2} COOH & \to_{H_{3} O^{\oplus}}^{KCN} & HOOC - {CH}_{2} - COOH \\ (Y) & (X) Malonic acid \end{matrix}

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