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$\mathrm{CH}_3 \mathrm{COOH} \stackrel{\mathrm{LiAlH}_4}{\longrightarrow} A$
$\mathrm{A}+\mathrm{CH}_3 \mathrm{COOH} \stackrel{\mathrm{H}_3 \mathrm{O}^{+}}{\longrightarrow} \mathrm{B}+\mathrm{H}_2 \mathrm{O}$
In the above reactions ' $A$ ' and ' $B$ ' respectively are
Options:
$\mathrm{A}+\mathrm{CH}_3 \mathrm{COOH} \stackrel{\mathrm{H}_3 \mathrm{O}^{+}}{\longrightarrow} \mathrm{B}+\mathrm{H}_2 \mathrm{O}$
In the above reactions ' $A$ ' and ' $B$ ' respectively are
Solution:
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Verified Answer
The correct answer is:
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}, \mathrm{CH}_3 \mathrm{COOC}_2 \mathrm{H}_5$
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