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$\mathrm{CH}_{3} \mathrm{COOH} \stackrel{\mathrm{LiAlH}_{4}}{\longrightarrow} \mathrm{X} \underset{300^{\circ} \mathrm{C}}{\stackrel{\mathrm{Cu}}{\longrightarrow}} \mathrm{Y} \underset{\mathrm{NaOH}}{\stackrel{\text { Dilute }}{\longrightarrow}} \mathrm{Z}$
In the above reaction $Z$ is
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In the above reaction $Z$ is
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The correct answer is:
aldol

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