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Change in temperature of the medium changes
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The correct answer is:
wavelength of sound waves
wavelength of sound waves
As we know that,
$$
v_t=v_0(1+0.61 t)
$$
Speed of sound wave in a medium $v \propto \sqrt{T}$
(where $T$ is temperature of the medium)
Clearly, when temperature increase then the speed also increase as frequency does not change during propogation of wave by formula.
As, $v=v \lambda$
where $v$ is frequency and $\lambda$ is wavelength.
Frequency $(v)$ remains fixed,
$v \propto \lambda$ or $\lambda \propto v$
So velocity $v$ and wavelength $(\lambda)$ both increases.
$$
v_t=v_0(1+0.61 t)
$$
Speed of sound wave in a medium $v \propto \sqrt{T}$
(where $T$ is temperature of the medium)
Clearly, when temperature increase then the speed also increase as frequency does not change during propogation of wave by formula.
As, $v=v \lambda$
where $v$ is frequency and $\lambda$ is wavelength.
Frequency $(v)$ remains fixed,
$v \propto \lambda$ or $\lambda \propto v$
So velocity $v$ and wavelength $(\lambda)$ both increases.
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