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Ethers are readily cleaved by action of $\mathrm{HI}$ to form alcohol and alkyl halide.
$R-\mathrm{O}-\mathrm{R}+\mathrm{HX} \longrightarrow \mathrm{RX}+\mathrm{R}-\mathrm{OH}$
If excess of halogen acid is used, then alcohol formed reacts further with halogen acid to produce alkyl halide.
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