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ChemistryChemical Bonding and Molecular StructureAP EAMCETAP EAMCET 2004
Options:
  • A $\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \\3 & 4 & 1 & 2\end{array}$
  • B $\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \\ 4 & 5 & 3 & 2\end{array}$
  • C $\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \\ 3 & 1 & 2 & 5\end{array}$
  • D $\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \\ 2 & 3 & 4 & 5\end{array}$
Solution:
1186 Upvotes Verified Answer
The correct answer is: $\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \\3 & 4 & 1 & 2\end{array}$
Ethane $\mathrm{CH}_3-\mathrm{CH}_3\ 2 s p^3$-hybrid carbon
Ethylene $\mathrm{CH}_2=\mathrm{CH}_2\ 2 s p^2$-hybrid carbon
Acetylene $\mathrm{CH} \equiv \mathrm{CH}\ 2 s p$-hybrid carbon
Benzene < smiles>c1ccccc1 < /smiles>$6 s p^2$-hydrid carbon

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