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Verified Answer
The correct answer is:
$\frac{{{\mu }_{o}}l\lambda }{2\pi R}ln\frac{x}{{{x}_{o}}}$
Correct Option is : (B)
$\frac{{{\mu }_{o}}l\lambda }{2\pi R}ln\frac{x}{{{x}_{o}}}$
$\frac{{{\mu }_{o}}l\lambda }{2\pi R}ln\frac{x}{{{x}_{o}}}$
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