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$\int \frac{d x}{\sin ^2 x \cos ^2 x} \text { equals }$
(a) $\tan x+\cot x+C \quad$
(b) $\tan x-\cot x+C$
(c) $\tan x \cot x+C$
(d) $\tan x-\cot 2 x+C$
$\int \frac{d x}{\sin ^2 x \cos ^2 x} \text { equals }$
(a) $\tan x+\cot x+C \quad$
(b) $\tan x-\cot x+C$
(c) $\tan x \cot x+C$
(d) $\tan x-\cot 2 x+C$
Solution:
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Verified Answer
(b) $\int \frac{d x}{\sin ^2 x \cos ^2 x}=\int \frac{\sin ^2 x+\cos ^2 x}{\sin ^2 x \cos ^2 x} d x$ $=\int\left(\sec ^2 x+\operatorname{cosec}^2 x\right) d x=\tan x-\cot x+C$
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