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$\int \frac{10 x^9+10^x \log e^{10}}{x^{10}+10^x} d x$
(a) $10^x-x^{10}+C$
(b) $10^x+x^{10}+C$
(c) $\left(10^x-x^{10}\right)^{-1}+C$
(d) $\log \left(10^x+x^{10}\right)+C$
$\int \frac{10 x^9+10^x \log e^{10}}{x^{10}+10^x} d x$
(a) $10^x-x^{10}+C$
(b) $10^x+x^{10}+C$
(c) $\left(10^x-x^{10}\right)^{-1}+C$
(d) $\log \left(10^x+x^{10}\right)+C$
Solution:
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Verified Answer
(d) $\int \frac{10 x^9+10^x \log e^{10}}{x^{10}+10^x} d x=\log \left(x^{10}+10^x\right)+\mathrm{C}$
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