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Choose the correct circuit which can achieve the bridge balance.
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In option (4),
$\frac{10}{15}=\frac{10}{5+R_D}$
The diode can conduct and have resistance $R_D=10 \Omega$ because diode have dynamic resistance. In that case bridge will be balanced
$\frac{10}{15}=\frac{10}{5+R_D}$
The diode can conduct and have resistance $R_D=10 \Omega$ because diode have dynamic resistance. In that case bridge will be balanced
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