Search any question & find its solution
Question:
Answered & Verified by Expert
Circles $x^2+y^2-2 x-4 y=0$ and $x^2+y^2-8 y-4=0$
Options:
Solution:
1220 Upvotes
Verified Answer
The correct answer is:
Touch each other internally
$C_1(1,2), C_2(0,4), R_1=\sqrt{5}, R_2=2 \sqrt{5}$
$C_1 C_2=\sqrt{5}$ and $C_1 C_2=\left|R_2-R_1\right|$
Hence circles touch internally.
$C_1 C_2=\sqrt{5}$ and $C_1 C_2=\left|R_2-R_1\right|$
Hence circles touch internally.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.