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$\mathrm{Cl}_{2} \mathrm{O}_{7}$ is the anhydride of
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The correct answer is:
$\mathrm{HClO}_{4}$
$\mathrm{Cl}_{2} \mathrm{O}_{7}$ is the anhydride of $\mathrm{HClO}_{4}$. It reacts with water slowly to give perchloric acid.
$\mathrm{Cl}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \underset{\text { Perchloric acid }}{2 \mathrm{HClO}_{4}}$
Its structure is as follows:
It is less reactive than other oxides of chlorine and does not react with $P, S,$ coal or paper at room temperature.
$\mathrm{Cl}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \underset{\text { Perchloric acid }}{2 \mathrm{HClO}_{4}}$
Its structure is as follows:
It is less reactive than other oxides of chlorine and does not react with $P, S,$ coal or paper at room temperature.
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