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Question:
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$$
\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right] \mathrm{Br} \text { and }\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right] \mathrm{SO}_4
$$
are a pair of isomers.
Options:
\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right] \mathrm{Br} \text { and }\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right] \mathrm{SO}_4
$$
are a pair of isomers.
Solution:
2094 Upvotes
Verified Answer
The correct answer is:
ionisation
$$
\begin{aligned}
& {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right] \mathrm{Br} \rightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right]^{+}+\mathrm{Br}^{-}} \\
& {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right] \mathrm{SO}_4 \rightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right]^{2+}+\mathrm{SO}_4^{2-}}
\end{aligned}
$$
the molecular formula of both of the above compounds is same but on ionisation they give different ions in solution, so they are called ionisation isomers.
\begin{aligned}
& {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right] \mathrm{Br} \rightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right]^{+}+\mathrm{Br}^{-}} \\
& {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right] \mathrm{SO}_4 \rightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right]^{2+}+\mathrm{SO}_4^{2-}}
\end{aligned}
$$
the molecular formula of both of the above compounds is same but on ionisation they give different ions in solution, so they are called ionisation isomers.
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