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Coersivity of a magnet where the ferromagnet gets completely demagnetized is \( 3 \times 10^{3} \mathrm{Am}^{-1} \)
The minimum current required to be passed in a solenoid having \( 1000 \) turns per metre, so
that the magnet gets completely demagnetized when placed inside the solenoid is
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The minimum current required to be passed in a solenoid having \( 1000 \) turns per metre, so
that the magnet gets completely demagnetized when placed inside the solenoid is
Solution:
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Verified Answer
The correct answer is:
\( 3 \mathrm{~A} \)
(A)
\( H=n l \)
\( \therefore I=\frac{H}{n}=\frac{3 \times 10^{3}}{1000}=3 \mathrm{~A} \)
\( H=n l \)
\( \therefore I=\frac{H}{n}=\frac{3 \times 10^{3}}{1000}=3 \mathrm{~A} \)
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