Combustion of glucose takes place according to the equation C 6 H 12 O 6 + 6 O 2 → 6 CO 2 + 6 H 2 O; ΔH = − 72 kcal/mol . How much energy will be released by the combustion of 1 .6 g of glucose (Molecular mass of glucose = 180 g/mol )?

Question

Combustion of glucose takes place according to the equation C 6 H 12 O 6 + 6 O 2 → 6 CO 2 + 6 H 2 O; ΔH = − 72 kcal/mol . How much energy will be released by the combustion of 1 .6 g of glucose (Molecular mass of glucose = 180 g/mol )?, 0.064 kcal, 0.64 kcal, 6.4 kcal, 64 kcal

MARKS App · Accepted Answer

Combustion of glucose takes place according to the equation C 6 H 12 O 6 + 6O 2 → 6CO 2 + 6H 2 O; ΔH = -72 kcal ΔH per 1 .6 g = 72×1 .6 180 = 0 .64 kcal

Search any question & find its solution

Looking for more such questions to practice?