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Question: Answered & Verified by Expert
Common alum is
Chemistrys Block ElementsJIPMERJIPMER 2010
Options:
  • A $\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O}$
  • B $\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4 \cdot \mathrm{FeSO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O}$
  • C $\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Cr}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O}$
  • D $\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O}$
Solution:
1099 Upvotes Verified Answer
The correct answer is: $\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O}$
Common alum is $\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O}$.

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