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Compare the relative stability of the following species and indicate their magnetic properties:
\(\mathrm{O}_2, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}\)(superoxide), \(\mathrm{O}_2^{2-}\) (peroxide)
ChemistryChemical Bonding and Molecular Structure
Solution:
2485 Upvotes Verified Answer
The electronic configuration of
\(\mathrm{O}_2=K K \sigma(2 s)^2 \quad \sigma^*(2 s)^2 \quad \sigma\left(2 p_z\right)^2 \quad \pi\left(2 p_y\right)^2\)
\(\pi\left(2 p_x\right)^2 \pi^*\left(2 p_y\right)^1 \pi^*\left(2 p_x\right)^1\)
The number of bonding electrons \(\left(\mathrm{N}_b\right)=8\), number of anti-bonding electrons \(\left(\mathrm{N}_a\right)=4\)
Bond order \(=\frac{\mathrm{N}_b-\mathrm{N}_a}{2}=1 / 2(8-4)=2\),
It is paramagnetic due to presence of 2 unpaired electrons in the \(\pi^*\left(2 p_y\right)\) and \(\pi^*\left(2 p_z\right)\).
The electronic configuration of \(\mathrm{O}_2^{+}=K K \sigma(2 s)^2 \sigma^*(2 s)^2 \sigma\left(2 p_z\right)^2 \pi\left(2 p_y\right)^2 \pi\left(2 p_x\right)^2 \pi^*\left(2 p_y\right)^1\) The number of bonding electrons \(\left(\mathrm{N}_b\right)=8\), number of anti-bonding electrons \(\left(\mathrm{N}_a\right)=3\)
Bond order \(=\frac{\mathrm{N}_b-\mathrm{N}_a}{2}=1 / 2(8-3)=2 \frac{1}{2}\), It is paramagnetic due to presence of 1 unpaired electrons in the \(\pi^*\left(2 p_y\right)\).
The electronic configuration of \(\mathrm{O}_2^{-1}\) (super-oxide) \(=K K\) \(\sigma(2 s)^2 \sigma *(2 s)^2 \sigma\left(2 p_z\right)^2 \pi\left(2 p_y\right)^2 \pi\left(2 p_x\right)^2 \pi^*\left(2 p_y\right)^2 \pi^*\left(2 p_z\right)^1\) The number of bonding electrons \(\left(\mathrm{N}_b\right)=8\), number of anti-bonding electrons \(\left(\mathrm{N}_a\right)=5\)
Bond order \(=\frac{\mathrm{N}_b-\mathrm{N}_a}{2}=1 / 2(8-5)=1 \frac{1}{2}\),
It is paramagnetic due to presence of lunpaired electrons in the \(\pi^*\left(2 p_y\right)\)
The electronic configuration of \(\mathrm{O}_2^{2-}\) ( peroxide) \(=K K \sigma\) \((2 s)^2 \sigma^*(2 s)^2 \sigma\left(2 p_x\right)^2 \pi\left(2 p_y\right)^2\) \(\pi\left(2 p_z\right)^2 \pi^*\left(2 p_y\right)^2 \pi *\left(2 p_z\right)^2\)
The number of bonding electrons \(\left(\mathrm{N}_b\right)=8\), number of anti-bonding electrons \(\left(\mathrm{N}_a\right)=6\)
Bond order \(=\frac{\mathrm{N}_b-\mathrm{N}_a}{2}=1 / 2(8-6)=1\),
It is dia-magnetic due to presence of no unpaired electrons.
The relative stability would be \(\mathrm{O}_2{ }^{+}>\mathrm{O}_2>\mathrm{O}_2^{-}\) \(>\mathrm{O}_2{ }^{2-}\) since higher the bond order more is the stability.

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