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Complete reduction of benzene-diazonium chloride with $\mathrm{Zn} / \mathrm{HCl}$ gives:
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Aniline
Aniline
On reduction with $\mathrm{Zn}$ and $\mathrm{HCl}, \mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}_2 \mathrm{Cl}$ forms aniline as the main product.
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