$\underset{\text{shows}\text{iodoform}\text{test}}{\underset{{\text{C}}_{\text{9}}{\text{H}}_{\text{10}}\text{O}}{\text{A}}}\stackrel{{\text{KMnO}}_{\text{4}}\text{/KOH}}{\to }\underset{\text{Acid}}{\underset{{\text{C}}_{\text{8}}{\text{H}}_{\text{6}}{\text{O}}_{\text{4}}}{\text{B}}}$
Note : Anhydride of B is used in preparation of phenolphthalein.
$\Rightarrow$ B must be phthalic acid as phthalic anhydride is used in preparation of phenolphthalein.

$\Rightarrow$ Option 3 is wrong because it doesn't give iodoform test