$=\left(1\right)2{\mathrm{AgNO}}_3+2\mathrm{KOH}⟶{\mathrm{Ag}}_2\mathrm{O}\downarrow \left(\text{ black }\right)+2{\mathrm{KNO}}_3+{\mathrm{H}}_2\mathrm{O}$

$\downarrow \mathrm{excess} \mathrm{KOH}$

No reaction

$\text{ (2) }{\mathrm{AgNO}}_3 \stackrel{{\mathrm{CN}}^{-}}{⟶}\text{ AgCN }\downarrow \text{ (white) }\frac{{\mathrm{CN}}^{-}}{\text{excess }}\mathrm{Ag}(\mathrm{CN}{)}_2^{-}$

(Soluable)

$\text{ (3) }{\mathrm{AgNO}}_3 \stackrel{{\mathrm{S}}_2{\mathrm{O}}_3^{2-}}{⟶}{\mathrm{Ag}}_2{\mathrm{S}}_2{\mathrm{O}}_3\downarrow \text{ (white) }\frac{{\mathrm{S}}_2{\mathrm{O}}_3^{2-}}{\text{ excess }}$

$\mathrm{Ag}{\left({\mathrm{S}}_2{\mathrm{O}}_3\right)}_2^{3-}$ (Soluable)

$\text{ (4) }{\mathrm{AgNO}}_3\stackrel{{\mathrm{NH}}_3}{⟶}{\mathrm{Ag}}_2\mathrm{O}\downarrow \text{ (black) }\frac{{\mathrm{NH}}_3}{\text{ excess }}{\left[\mathrm{Ag}{\left({\mathrm{NH}}_3\right)}_2\right]}^{+}$

(Soluable)

Hence (2), (3) &(4) are not the answers