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Compute $P(A \mid B)$ if $P(B)=0.5$ and $\mathbf{P}(\mathrm{A} \cap \mathrm{B})=\mathbf{0 . 3 2}$.
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Verified Answer
Given : $\mathrm{P}(\mathrm{B})=0.5, \mathrm{P}(\mathrm{A} \cap \mathrm{B})=0.32$
$$
P(A \mid B)=\frac{P(A \cap B)}{P(B)}=\frac{0.32}{0.50}=\frac{32}{50}=0.64
$$
$$
P(A \mid B)=\frac{P(A \cap B)}{P(B)}=\frac{0.32}{0.50}=\frac{32}{50}=0.64
$$
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