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Concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ reacts with $\mathrm{PCl}_{5}$ to produce
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$\mathrm{SO}_{2} \mathrm{Cl}_{2}$
When excess of $\mathrm{Pa}_{5}$ reacts with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$, it gives suphuryl chloride $\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)$ as product


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