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Question: Answered & Verified by Expert
Concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ reacts with $\mathrm{PCl}_{5}$ to produce
Chemistryp Block Elements (Group 15, 16, 17 & 18)MHT CETMHT CET 2020 (13 Oct Shift 2)
Options:
  • A $\mathrm{HClO}_{2}$
  • B $\mathrm{SO}_{2} \mathrm{Cl}_{2}$
  • C $\mathrm{SOCl}_{2}$
  • D $\mathrm{HClO}_{4}$
Solution:
1299 Upvotes Verified Answer
The correct answer is: $\mathrm{SO}_{2} \mathrm{Cl}_{2}$
When excess of $\mathrm{Pa}_{5}$ reacts with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$, it gives suphuryl chloride $\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)$ as product

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