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Concentrated $\mathrm{HNO}_3$ reacts with $I_2$ to give
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$\mathrm{HIO}_3$
$I_2+10 \mathrm{HNO}_3 \rightarrow 2 \mathrm{HIO}_3+10 \mathrm{NO}_2+4 \mathrm{H}_2 \mathrm{O}$
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