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Question: Answered & Verified by Expert
Consider a matrix A=aij3×3 where, aij=i+2jij=even2i-3jij=odd. If bij is the cofactor of aij in matrix A and Cij=r=13airbjr, then Cij3×3 is
MathematicsMatricesJEE Main
Options:
  • A 100010001
  • B -15-746839-3
  • C 184000184000184
  • D 231162-152
Solution:
2032 Upvotes Verified Answer
The correct answer is: 184000184000184
A=a11a12a13a21a22a23a31a32a33=-15-746837-3
B=b11b12b13b21b22b23b31b32b33
A=-1-18-56-5-12-24-728-18
=184
Cij=ai1bj1+ai2bj2+ai3bj3
C11=a11b11+a12b12+a13b13=A
C12=a11b21+a12b22+a13b23=0
Similarly,
C13=0,C21=0,C22=A,C23=0,C31=0
C32=0,C33=A
Cij3×3=A000A000A=184000184000184

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