Consider a radioactive nucleus which decays to a stable nucleus C through the following sequence $ A → B → C Here \mathrm{B} i s anin t er m e d ia t e n u c l e i w hi c hi s a l sor a d i o a c t i v e . C o n s i d er in g t ha tt h ere a re \mathrm{N}_0 a t o m so f \mathrm{A} ini t ia ll y , pl o tt h e g r a p h s h o w in g t h e v a r ia t i o n o f n u mb ero f a t o m so f A an d B$ versus time.

Question

Consider a radioactive nucleus which decays to a stable nucleus C through the following sequence $ A → B → C Here \mathrm{B} i s anin t er m e d ia t e n u c l e i w hi c hi s a l sor a d i o a c t i v e . C o n s i d er in g t ha tt h ere a re \mathrm{N}_0 a t o m so f \mathrm{A} ini t ia ll y , pl o tt h e g r a p h s h o w in g t h e v a r ia t i o n o f n u mb ero f a t o m so f A an d B$ versus time.,

MARKS App · Accepted Answer

At t = 0 , N A ​ = N 0 ​ ( maximum ) while N B ​ = 0 . As time increases, N A ​ decreases exponentially and the number of atoms of B increases. They becomes ( N B ​ ) maximum and finally the drop to zero exponentially by radioactive decay law.

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