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Question: Answered & Verified by Expert

Consider a reaction that is first order in both directions



AkbkfB



Initially only A is present, and its concentration is A0. Assume At and Aeq are the concentrations of A at time "t" and at equilibrium, respectively. The time "t" at which At=A0+Aeq/2 is:


ChemistryChemical KineticsKVPYKVPY 2020 (SB/SX)
Options:
  • A t=ln32kf+kb
  • B t=ln32kf-kb
  • C t=ln2kf+kb
  • D t=ln2kf-kb
Solution:
2375 Upvotes Verified Answer
The correct answer is: t=ln2kf+kb

AB



t=0   A0  0



t=t  A0-x  x



=At



t=teq  A0-Xeq  Xeq



=Aeq 



Given at time t=t At=A0+Aaq2 and xeq.=A0-Aeq



Now, t=1kf+kblnxcxc-x=ln2kf+kb


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