Consider a region of space in which constant, uniform, and mutually perpendicular fields E → and B → exists. Now a particle of charge q enters this region with a velocity v → which is perpendicular to both the fields. If the velocity of the charge remains unchanged, then

Question

Consider a region of space in which constant, uniform, and mutually perpendicular fields E → and B → exists. Now a particle of charge q enters this region with a velocity v → which is perpendicular to both the fields. If the velocity of the charge remains unchanged, then, v → = B → × E → E 2, v → = E → × B → B 2, v → = B → × E → B 2, v → = E → × B → E 2

MARKS App · Accepted Answer

when E → and B → are perpendicular and velocity has no change then q E = q v B i . e . , v = E B . The two forces oppose each other so, v is along v → × B → i . e . , v → = E → × B → B 2 As E → and B → are perpendicular to each other E → × B → B 2 = E B sin ⁡ 90 o B 2 = E B

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