Consider single slit experiment of diffraction of light. If the light of wavelength 5000 A ∘ fall on a slit of width 1 μ m then the angular width of central maximum is

Question

Consider single slit experiment of diffraction of light. If the light of wavelength 5000 A ∘ fall on a slit of width 1 μ m then the angular width of central maximum is, 30 °, 15 °, 60 °, None of these

MARKS App · Accepted Answer

d sin ⁡ θ = λ sin ⁡ θ = λ d For first minima = 5 × 10 - 7 10 - 6 sin ⁡ θ = 5 10 θ = 30 ° Angular width of first minima 2 θ = 60 °

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