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Consider the circuit shown below where all resistors are of $1 \mathrm{k} \Omega$
If a current of magnitude $1 \mathrm{~mA}$ flows through the resistor marked $\mathrm{X}$, what is the potential difference measured between point $\mathrm{P}$ and $\mathrm{Q}$ ?
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If a current of magnitude $1 \mathrm{~mA}$ flows through the resistor marked $\mathrm{X}$, what is the potential difference measured between point $\mathrm{P}$ and $\mathrm{Q}$ ?
Solution:
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Verified Answer
The correct answer is:
$34 \mathrm{~V}$
Using KCL
At point $A$
Current is $3 \mathrm{~mA}$
At point $C$
Current is $8 \mathrm{~mA}$
At point $E$
Current is $21 \mathrm{~mA}$
At point $G$
Current through $\mathrm{GH}$ is 34 ma
$\begin{array}{l}
\therefore \mathrm{V}_{\mathrm{PQ}}=\mathrm{V}_{\mathrm{GH}}=\mathrm{i} \mathrm{R}_{\mathrm{GH}} \\
=34 \mathrm{~V}
\end{array}$
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