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Consider the circuit shown in the figure. The value of current ' $I$ ' is
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Verified Answer
The correct answer is:
$-\frac{7}{18} \mathrm{~A}$
Current from B to A, $\mathrm{I}_1=\frac{6-(-8)}{28}=0.5 \mathrm{~A}$
Current from $\mathrm{C}$ to $\mathrm{B}=\mathrm{I}_2=\frac{12-6}{54}=\frac{1}{9} \mathrm{~A}$
Hence, $\mathrm{I}=\mathrm{I}_2-\mathrm{I}_1=\frac{1}{9}-\frac{1}{2}=-\frac{7}{18} \mathrm{~A}$
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