Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Consider the equation \( x^{2}+2 x-n=0 \), where \( n \in N \) and \( n \in[5,100] . \) The total number of different values of \( n \) so that the given equation has integral roots is
MathematicsQuadratic EquationJEE Main
Options:
  • A \( 8 \)
  • B \( 3 \)
  • C \( 6 \)
  • D \( 4 \)
Solution:
1534 Upvotes Verified Answer
The correct answer is: \( 8 \)

We have,

x2+2x-n=0

We know that for a Quadratic equation ax2+bx+c=0, a0 the roots are x=-b±b2-4ac2a.

x=-1± n+1

Thus, n+1 should be a perfect square for integral roots.

Now,

n5,100n+16,101

Perfect square values of n+1 are 9,16,25,36,49,64,81,100

Hence, number of values is 8.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.