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Consider the following population and year graph, find the slope of the line $A B$ and using it, find what will be the population in the year 2010 ?
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Verified Answer
Slope of the line joining the point $A(1985,92)$ and $B(1995,97)$
$=\frac{97-92}{1995-1985}=\frac{5}{10}=\frac{1}{2}$
Let $P$ be the population in the year 2010
$\therefore \quad$ The point $P(2010, \mathrm{P})$ lies on it
$\therefore$ Slope of $B P=$ Slope of $A B$
Slope of $B P=\frac{P-97}{2010-1995}=\frac{1}{2}$
$\Rightarrow \quad 2(P-97)=2010-1995=15$
$P-97=\frac{15}{2} \Rightarrow P=97+7.5$
$\therefore \quad P=104.5 \text { crores }$
$=\frac{97-92}{1995-1985}=\frac{5}{10}=\frac{1}{2}$
Let $P$ be the population in the year 2010
$\therefore \quad$ The point $P(2010, \mathrm{P})$ lies on it
$\therefore$ Slope of $B P=$ Slope of $A B$
Slope of $B P=\frac{P-97}{2010-1995}=\frac{1}{2}$
$\Rightarrow \quad 2(P-97)=2010-1995=15$
$P-97=\frac{15}{2} \Rightarrow P=97+7.5$
$\therefore \quad P=104.5 \text { crores }$
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