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Question: Answered & Verified by Expert
Consider the following reaction equilibrium

N2g+3H2(g)2NH3(g)

Initially, 1 mole of N2 and 3 moles of H2 are taken in a 2 L flask. At equilibrium state if, the number of moles of Nis 0.6, what is the total number of moles of all gases present in the flask?
ChemistryChemical EquilibriumNEET
Options:
  • A 0.8
  • B 1.6
  • C 3.2
  • D 6.4
Solution:
1468 Upvotes Verified Answer
The correct answer is: 3.2


Number of moles of N2=0.6=1-x

x=1-0.6=0.4

So, 3-3x=3-3×0.4=1.8,

and 2x=2×0.4=0.8

Therefore, the total number of moles at equilibrium.

=1-x+3-3x+2x

=0.6+1.8+0.8

=3.2 mol

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