Consider the following reactions NaCl + K 2 C r 2 O 7 + Conc . H 2 SO 4 → A + side products A + NaOH → B + side products B + dilute H 2 SO 4 + H 2 O 2 → C + Side products The sum of atoms in one molecule each of (A), (B) and (C) is

Question

Consider the following reactions NaCl + K 2 C r 2 O 7 + Conc . H 2 SO 4 → A + side products A + NaOH → B + side products B + dilute H 2 SO 4 + H 2 O 2 → C + Side products The sum of atoms in one molecule each of (A), (B) and (C) is,

MARKS App · Accepted Answer

The reaction is as follows NaCl → K 2 Cr 2 O 7 /H ⊕ CrO 2 Cl 2 A → NaOH Na 2 CrO 4 B → H ⊕ H 2 O 2 CrO 5 C Cr O 2 C l 2 → 5 N a 2 Cr O 4 → 7 CrO 5 → 6 , Total = 18

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