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Question: Answered & Verified by Expert
Consider the following relations for emf of an electrochemical cell

(i) EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode)

(ii) EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode)

(iii) EMF of cell = (reduction potential of anode) + (oxidation potential of cathode)

(iv) EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)

Which of these expressions are correct?
ChemistryElectrochemistryNEET
Options:
  • A (iii) and (i)
  • B (i) and (ii)
  • C (iii) and (iv)
  • D (ii) and (iv)
Solution:
1267 Upvotes Verified Answer
The correct answer is: (ii) and (iv)
EMF of a cell = reduction potential of cathode - reduction potential of anode

= reduction potential of cathode + oxidation potential of anode

= oxidation potential of anode - oxidation potential of cathode.

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