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Consider the following relations for emf of an electrochemical cell
EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode)
EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode)
EMF of cell = (reduction potential of anode) + (oxidation potential of cathode)
EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)
Which of these expressions are correct?
Options:
EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode)
EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode)
EMF of cell = (reduction potential of anode) + (oxidation potential of cathode)
EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)
Which of these expressions are correct?
Solution:
1267 Upvotes
Verified Answer
The correct answer is:
(ii) and (iv)
EMF of a cell = reduction potential of cathode - reduction potential of anode
= reduction potential of cathode + oxidation potential of anode
= oxidation potential of anode - oxidation potential of cathode.
= reduction potential of cathode + oxidation potential of anode
= oxidation potential of anode - oxidation potential of cathode.
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