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Question: Answered & Verified by Expert
Consider the following relations from $A$ to $B$ where $A=\{u, v, w, x, y, z\}$ and $B=\{p, q, r, s\}$
1.$\{(u, p),(v, p),(w, p),(x, q),(y, q),(z, q)\}$
2.\{(u, p),(v, q),(w, r),(z, s)\}
3.\{(u, s),(v, r),(w, q),(u, p),(v, q),(z, q)
4.$\{(u, q),(v, p),(w, s),(x, r),(y, q),(z, s)$
Which of the above relations are not functions ?
MathematicsSets and RelationsNDANDA 2014 (Phase 1)
Options:
  • A 1 and 2
  • B 1 and 4
  • C 2 and 3
  • D 3 and 4
Solution:
1891 Upvotes Verified Answer
The correct answer is: 2 and 3
Given that, $A=\{u, v, x, y, z\} ; B=\{p, q, r, s\}$ As we know, a mapping $\mathrm{f}: \mathrm{x} \rightarrow \mathrm{y}$ is said to be a function if each element in the set $\mathrm{x}$ has its image in set $\mathrm{y} .$ It $\mathrm{k}$
also possible that these are few elements in set y which are not the image of any element in set $\mathrm{x}$. Every element
in set $x$ should have one and only one image.
(i)


(ii)

(iii)

(iv)

(ii) and (iii) are not function

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