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Consider the following sets of quantum numbers. Which of the below setting is not permissible arrangement of electrons in an atom?
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Verified Answer
The correct answer is:
\(\mathrm{n}=3,1=2, \mathrm{~m}=-3, \mathrm{~s}=+2\)
The value of azimuthal quantum number \( l=n-1 \).
The value of magnetic quantum number \( m_{1}=-l \) to \( +l \)
\begin{array}{|l|l|l|l|l|}
\hline Quantum Numbers & \( \mathrm{n} \) & \( 1 \) & \( m_{1} \) & \( m_{s} \) \\
\hline PossibleValues & \( 3 \) & \( 0,1,2 \) & \( -2,-1,0,+1,+2 \) & \( +\frac{1}{2} \) and \( -\frac{1}{2} \) \\
\hline
\end{array}
Therefore, \( m_{1}=-3 \) is not possible for \( n=3 \).
The value of magnetic quantum number \( m_{1}=-l \) to \( +l \)
\begin{array}{|l|l|l|l|l|}
\hline Quantum Numbers & \( \mathrm{n} \) & \( 1 \) & \( m_{1} \) & \( m_{s} \) \\
\hline PossibleValues & \( 3 \) & \( 0,1,2 \) & \( -2,-1,0,+1,+2 \) & \( +\frac{1}{2} \) and \( -\frac{1}{2} \) \\
\hline
\end{array}
Therefore, \( m_{1}=-3 \) is not possible for \( n=3 \).
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