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Consider the following statements:
I. Increase in concentration of reactant increases the rate of a zero order reaction.
II. Rate constant $\mathrm{k}$ is equal to collision frequency $\mathrm{A}$ if $\mathrm{E}_{\mathrm{a}}=0$.
III. Rate constant $\mathrm{k}$ is equal to collision frequency $\mathrm{A}$ if $\mathrm{E}_{\mathrm{a}}=\infty$.
IV. In $\mathrm{k}$ vs $\mathrm{T}$ is a straight line.
$\mathrm{V}$. In $\mathrm{k}$ vs $1 / \mathrm{T}$ is a straight line.
Correct statements are
Options:
I. Increase in concentration of reactant increases the rate of a zero order reaction.
II. Rate constant $\mathrm{k}$ is equal to collision frequency $\mathrm{A}$ if $\mathrm{E}_{\mathrm{a}}=0$.
III. Rate constant $\mathrm{k}$ is equal to collision frequency $\mathrm{A}$ if $\mathrm{E}_{\mathrm{a}}=\infty$.
IV. In $\mathrm{k}$ vs $\mathrm{T}$ is a straight line.
$\mathrm{V}$. In $\mathrm{k}$ vs $1 / \mathrm{T}$ is a straight line.
Correct statements are
Solution:
1168 Upvotes
Verified Answer
The correct answer is:
II and V
According to Arrhenius equation, $\mathrm{k}=\mathrm{Ae}^{-\mathrm{E}_{\mathrm{a}} / \mathrm{RT}}$ $\therefore$ when $\mathrm{E}_{\mathrm{a}}=0, \mathrm{k}=\mathrm{A}$ Also $\ln \mathrm{k}$ vs $1 / \mathrm{T}$ is a straight line with slope $=-$ $\mathrm{E}_2 / \mathrm{R}$. $\therefore$ Statements (ii) and (v) are correct.
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