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Determine the point of application of force, when forces of $20 \mathrm{~N}$ and $30 \mathrm{~N}$ are acting on a rod as shown in figure
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Verified Answer
The correct answer is:
$70 \mathrm{~cm}$
Net force acting on the rod, $\mathrm{F}_{\text {rel }}=10 \mathrm{~N}$
Net torque acting on the rod about point $\mathrm{C}$ is
$\tau_c=(20 \times 0)+(30 \times 20)=600 \text { clockwise }$
Let the point of application be at a distance $x$ from point $C$
$600=10 \mathrm{x} \Rightarrow \mathrm{x}=60 C M$
Therefore, $70 \mathrm{CM}$ from $\mathrm{A}$ is the point of application of force.
Net torque acting on the rod about point $\mathrm{C}$ is
$\tau_c=(20 \times 0)+(30 \times 20)=600 \text { clockwise }$
Let the point of application be at a distance $x$ from point $C$
$600=10 \mathrm{x} \Rightarrow \mathrm{x}=60 C M$
Therefore, $70 \mathrm{CM}$ from $\mathrm{A}$ is the point of application of force.
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