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Question: Answered & Verified by Expert
Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of Ka as 6.8×10-4,1.8×10-4 and 4.8×10-9 respectively. What will be the order of their acidic strength?
ChemistryIonic EquilibriumNEET
Options:
  • A HF > HCN > HCOOH
  • B HF > HCOOH > HCN
  • C HCN > HF > HCOOH
  • D HCOOH > HCN > HF
Solution:
1874 Upvotes Verified Answer
The correct answer is: HF > HCOOH > HCN
Solution which has higher Ka value will have more acidic strength .
So, KaHF6.8×10-4>HCOOH1.8×10-4>HCN4.8×10-9

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