Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of K a as 6.8 × 1 0 - 4 , 1.8 × 1 0 - 4 and 4.8 × 1 0 - 9 respectively. What will be the order of their acidic strength?

Question

Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of K a as 6.8 × 1 0 - 4 , 1.8 × 1 0 - 4 and 4.8 × 1 0 - 9 respectively. What will be the order of their acidic strength?, HF > HCN > HCOOH, HF > HCOOH > HCN, HCN > HF > HCOOH, HCOOH > HCN > HF

MARKS App · Accepted Answer

Solution which has higher Ka value will have more acidic strength . So, K a H F 6.8 × 1 0 - 4 > H C O O H 1.8 × 1 0 - 4 > H C N 4.8 × 1 0 - 9

Search any question & find its solution

Looking for more such questions to practice?