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Question: Answered & Verified by Expert
For a simple pendulum, a graph is plotted between its kinetic energy \( (K . E .) \) and potential energy \( (P . E .) \) against its
displacement \( d \). Which one of the following represents these correctly?
PhysicsOscillationsJEE Main
Options:
  • A
  • B
  • C
  • D
Solution:
1647 Upvotes Verified Answer
The correct answer is:

In simple harmonic motion, kinetic energy is given by,

K.E.=12kA2-d2.

So, the graph is a downward parabola.

Here, A=amplitude of simple harmonic motion

and d=displacement from mean position in simple harmonic motion
and

P.E.=12kd2.

So, the graph is an upward parabola.

At mean, d=0K.E.=12KA2

and potential energy is, P.E.=0.

At extreme positions,

d=AK.E.=0.

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