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Question: Answered & Verified by Expert
From a circular disc of radius R and mass 9M, a small disc of radius R3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is

PhysicsRotational MotionJEE Main
Options:
  • A 4 MR2
  • B 409 MR2
  • C 10 MR2
  • D 379 MR2
Solution:
1675 Upvotes Verified Answer
The correct answer is: 4 MR2
Iremaining=Iwhole-Iremoved

or I=129MR2-12mR32+12m2R32 ...(i)

Here, m=9MπR2×πR32=M

Substituting in Eq. (i), we have

I=4MR2

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